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Preparation of Chlorine

The gaseous p...

Question

The gaseous product of the reaction between $S n$ and conc. $H_{2} S O_{4}$ is :

A

H_{2}

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B

S O_{2}

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C

S n H_{4}

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D

S O_{3}

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Solution

The correct option is B $S O_{2}$
Tin react with sulfuric acid to produce tin(II) sulfate, sulfur dioxide and water.

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Similar questions

Q. The major products obtained in the reaction of oxalic acid with conc.

H_{2} S O_{4}

upon heating are:

Q. Catalyst used industrially which speeds up the conversion of

S O_{2}

S O_{3}

in the production of

H_{2} S O 4

in the laboratory or industrially. Write the equation for the conversion of

S O_{2}

S O_{3}

. Why does this reaction supply energy. What is the name of the compound formed between

S O_{3}

H_{2} S O_{4}

Q. Sodium oxalate on heating with conc.

H_{2} S O_{4}

Q. Sulphur reacts with conc.

H_{2} S O_{4}

to give a gas A and, it reacts with conc.

H N O_{3}

to give a gas B. A and B respectivley are:

S + O_{2} \to S O_{2}

Δ H = - 298.2

S O_{2} + \frac{1}{2} O_{2} \to S O_{3}

Δ H = - 98.7

S O_{3} + H_{2} O \to H_{2} S O_{4}

Δ H = - 130.2

H_{2} + \frac{1}{2} O_{2} \to H_{2} O

Δ H = - 287.3

Then the enthalpy of formation of

H_{2} S O_{4}

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