The general formula of primary, secondary and tertiary alcohol respectively are:

- C H_{2} O H

;

- C H R O H

;

- C R_{2} O H

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- C H R O H

;

- C R_{2} O H

;

C H_{2} O H;

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- C H R O H

;

C H_{2} O H

;

- C R_{2} O H

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none of the above

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Solution

The correct option is A $- C H_{2} O H$ ; $- C H R O H$ ; $- C R_{2} O H$
In primary alcohol, $- O H$ group is attached to a $C$ atom which itself is attached to $2 H$ and one other $C$ atom. Thus, $C H_{3} - C H_{2} - O H$ is primary alcohol.

In secondary alcohol, $- O H$ group is attached to a $C$ atom which itself is attached to $H$ and two other $C$ atom. Thus, $(C H_{3})_{2} - C H - O H$ is secondary alcohol.

In tertiary alcohol, $- O H$ group is attached to a $C$ atom which itself is attached to 3 other $C$ atoms. Thus, $(C H_{3})_{3} - C - O H$ is tertiary alcohol.

The general formula of primary, secondary and tertiary alcohol are $- C H_{2} O H$ ; $- C H R O H$ ; $- C R_{2} O H$ respectively.

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