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Reimer Tiemann Reaction

CH2OH ...

Question

$C H_{2} O H$
$|$
Acetaldehyde can be converted into HO $C H_{2} - C - C H_{2} O H$ by which reagent?
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$C H_{2} O H$

A

K O H

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B

K O H

followed by

L A H

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C

excess of

H C H O

and

K O H

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D

K C N

followed by

S B H

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Solution

The correct option is D excess of $H C H O$ and $K O H$
One mole of acetaldehyde reacts with 3 moles of formaldehyde in alkaline medium to form the given product.
This is the crossed aldol condensation reaction.

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Similar questions

R - C H_{2} - C H_{2} O H

can be converted into

R C H_{2} C H_{2} C O O H

by the following sequence of steps:

R - C H_{2} - C H_{2} O H

can be converted to

R - C H_{2} C H_{2} C O O H

. The correct sequence of reagents is:

{C H}_{3} {C H}_{2} O H

can be converted into

{C H}_{3} C H O

R C H_{2} {C H}_{2} O H

can be converted to

R C H_{2} {C H}_{2} C O O H

by the following sequence of steps:

A) Grignard reagent	1) $H_{2} / P d - B a S O_{4}$
B) Clemmensen reduction	2) $N_{2} H_{4} / K O H / C H_{2} O H - C H_{2} O H$
C) Rosenmunds reduction	3) $C H_{3} M g X$
D) Wolf-Kishner reduction	4) $Z n - H g / C o n c . H C l$ 5) $H_{2} / N i$

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