$R - C H_{2} - C H_{2} O H$ can be converted into $R C H_{2} C H_{2} C O O H$ by the following sequence of steps:

P B r_{3}, K C N, H_{2} / P t

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P B r_{3}, K C N, H_{3} O^{+}

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H C N, P B r_{3}, H_{3} O^{+}

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K C N, H_{3} O^{+}

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Solution

The correct option is B $P B r_{3}, K C N, H_{3} O^{+}$
$R - C H_{2} - C H_{2} O H$ can be converted into $R C H_{2} C H_{2} C O O H$ by the following sequence of steps $P B r_{3}, K C N, H_{3} O^{+}$
$R - C H_{2} - C H_{2} O H P B r_{3} - -- \to R - C H_{2} - C H_{2} - B r K C N - -- \to R - C H_{2} - C H_{2} - C N H_{3} O^{+} - -- \to R C H_{2} C H_{2} C O O H$
When alcohol is treated with phosphorous tribromide, it gives alkyl bromide. Alkyl bromide reacts with $K C N$ to form alkyl cyanide. In this process, one carbon atom is introduced. The hydrolysis of alkyl cyanide gives the carboxylic acid.

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