The general formula of starch is

(

C_{6} H_{5} O_{6})_{n}

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(

C_{6} H_{10} O_{5})_{n}

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(

C_{12} H_{22} O_{11})_{n}

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(

C_{12} H_{24} O_{11})_{n}

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Solution

The correct option is B ( $C_{6} H_{10} O_{5})_{n}$
Starch is used as food reserves in plants. It is a polymer of glucose. It is formed by the attachment of glucose unit by glycosidic bonds. The basic formula of starch is (C $_{6}$ H $_{10}$ O $_{5}$ )n. It exists in two forms amylose and amylopectin. Amylose is formed by linkage of glucose by alpha 1,4 glucose unit. It is a linear polymer. Amylopectin is a branched polymer of glucose where two polymeric chains of glucose of alpha 1,4 glucose unit are linked by alpha 1,6 linkage.
So, the correct answer is option B.

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Similar questions

C_{12} H_{26} \to C_{6} H_{12} + C_{6} H_{14}

C_{12} H_{26} ⟶ C_{6} H_{12} + C_{6} H_{14}

C_{12} H_{22} O_{11} + H_{2} O H^{+} - - \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}

C_{12} H_{22} O_{11} + H_{2} O I n v e r t a s e - ----- \to C_{6} H_{12} O_{6} A + C_{6} H_{12} O_{6} B

C_{6} H_{12} O_{6} z y m a s e - --- \to 2 C_{2} H_{5} O H + 2 {C O}_{2}

A

B

C_{12} H_{22} O_{11} + H_{2} O \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}

2.12 \times 10^{- 4} L {m o l}^{- 1} {s e c}^{- 1}

27^{o} C

1.07 \times 10^{5} J {m o l}^{- 1}

37^{o} C

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