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Question

The general solution of differential equation dydx=logx is


  1. y = log x - x + c

  2. y = x log x + x + c

  3. y =x log x - x + c

  4. y = x + c


Solution

The correct option is C

y =x log x - x + c


Given equation can be written as dy=logx dxdy=logx dxy=x logxx+c

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