Question

The general solution of differential equation $\frac{dy}{dx}=logx$ is

• A. y =x log x - x + c
• B. y = x + c
• C. y = x log x + x + c
• D. y = log x - x + c

Answer 1

The correct option is A

y =x log x - x + c

Given equation can be written as $dy=logxdx\Rightarrow \int dy=\int logxdx\Rightarrow y=xlogx-x+c$