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Question

The general solution of sinx+sin5x=sin2x+sin4x is:

A
2nπ
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B
nπ
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C
nπ/3
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D
2nπ/3
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Solution

The correct option is C nπ/3
sinx+sin5x=sin2x+sin4x
2sin3xcos2x=2sin3xcosx
2sin3x[cos2xcosx]=0
2sin3x(2cosx+1)(cosx1)=0
Hence sin3x=0 or 2cosx+1=0 or cosx=1
The generalised solution is option C

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