The general solution of sinx+sin5x=sin2x+sin4x is:
A
2nπ
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B
nπ
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C
nπ/3
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D
2nπ/3
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Solution
The correct option is Cnπ/3 sinx+sin5x=sin2x+sin4x ⇒2sin3xcos2x=2sin3xcosx ⇒2sin3x[cos2x−cosx]=0 ⇒2sin3x(2cosx+1)(cosx−1)=0 Hence sin3x=0 or 2cosx+1=0 or cosx=1 The generalised solution is option C