The geometrical isomerism is not shown by:

C H_{3} - C H = N O H

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H O - N = N - O H

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(C H_{3})_{2} - C = N O H

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Solution

The correct option is D $(C H_{3})_{2} - C = N O H$
( $C H_{3})_{2} - C = N - O H$ has two $- C H_{3}$ groups on the same carbon

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