The correct option is
D Conditions for geometrical isomers:
1) Free rotation must be restricted.
2) Both the terminals must be attached with different groups.
3) Terminals must not be in perpendicular planes.
a has two same groups attached to the one of the terminal carbon of the double bond so it can't show geometrical isomerism
b has two same groups attached to the one of the terminal carbon of the double bond so it can't show geometrical isomerism
c has two same groups attached to the one of the terminal carbon of the double bond so it can't show geometrical isomerism
d has two different groups (H and Cl) attached to the terminal carbon of the both double bond so it can show geometrical isomerism
hence correct option is d.