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Question

The geometry and hybridisation of Xe in XeF4 is:

A
see-saw, sp3d
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B
octahedral, sp3d2
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C
pIanar, sp3d2
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D
T-shaped, sp3d3
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Solution

The correct option is C pIanar, sp3d2
The valence shell of Xe contains two electrons in 5s orbital and six electrons in 5p orbital. In the 5th orbit there is a place for d orbital and f orbital both of these are empty. Of the 5s and 5p electrons in the outermost orbit of Xe, two of the 5p orbital electrons get excited to the vacant 5d orbital resulting in 4 unpaired hybridized electrons, 2 in 5p and 2 in 5d orbitals.
And the shape is square planar.

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