Question

The geometry and magnetic property of ${\left[NiC{l}_4\right]}^2$, respectively, are:

• A. tetrahedral, paramagnetic
• B. tetrahedral, diamagnetic
• C. square planar, paramagnetic
• D. square planar, diamagnetic

Answer 1

The correct option is A tetrahedral, paramagnetic

$[NiC{l}_4{]}^{2-}$

${}_{28}Ni$ $4s^{2}3d^8$

$N{i}^{2+}$ $4s^{0}3d^8$

(Refer to Image)

$[NiC{l}_4{]}^{2-}$ has $2$ unpaired $e^{-}$ and hence is paramagnetic in nature. $[\mu =\sqrt{2(2+2)}=\sqrt{8}=2.82BM]$

It has $s{p}^3$ hybridization with tetrahedral geometry.