The correct option is B tetrahedral and square planar
Ni:3d8 4s2; under the influence of strong ligand CO in Ni(CO)4 : 3d10–sp3 hybridisation (tetrahedral). In Ni(PH3)Cl2, Ni2+:3d8–dsp2 hybridisation (2 electrons in 3d are forced to be paired up by strong ligand PH3)