The given compound can be synthesized by a $S_{N} 2$ reaction. Select both the haloalkane and nucleophile that will give the product.

${C H}_{2} = C H {C H}_{2} O {C H}_{2} C H = {C H}_{2}$

C H_{3} - C H = C H C l

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C H_{2} = C H C H_{2} C l

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C H_{2} = C H - C H_{2} O N a

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C H_{3} - C H = C H O N a

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Solution

The correct options are
B $C H_{2} = C H C H_{2} C l$
D $C H_{2} = C H - C H_{2} O N a$
${C H}_{2} = C H {C H}_{2} O {C H}_{2} C H = {C H}_{2}$ can be synthesized by the combination of halo alkane $H_{2} C = C H - {C H}_{2} C l$ and nucleophile $H_{2} C = C H - {C H}_{2} O N a$ .
$H_{2} C = C H - {C H}_{2} C l + H_{2} C = C H - {C H}_{2} O N a ⟶ {C H}_{2} = C H {C H}_{2} O {C H}_{2} C H = {C H}_{2} + N a C l$
In this reaction, the chloride ion of $H_{2} C = C H - {C H}_{2} C l$ is displaced with $H_{2} C = C H - {C H}_{2} O^{-}$ group.

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