Question

The given diagram indicates the energy levels of certain atom. When a electron moves from $2E$ level to $E$ level, a photon of wavelength $\lambda$ is emitted. The wavelength of photon emitted during its transition from $\frac{4E}{3}$ level to $E$ level is:

• A. $\frac{\lambda }{3}$
• B. $\frac{3\lambda }{4}$
• C. $\frac{4\lambda }{3}$
• D. $3\lambda$

Answer 1

The correct option is D $3\lambda$

According to given conditions,
$hv=2E-E$
$\frac{hc}{\lambda }=E$
$\therefore \lambda =\frac{hc}{E}$
Also, wavelength of photon when tansition occurs, from 4E/3 level to E level
$\frac{hc}{{\lambda }_1}=4E/3-E=\frac{E}{3}$
${\lambda }_1=\frac{hc\times 3}{E}=3\lambda$