The given figure shows the electic line of force. If the electric fields at A,B,C and D are $E_{A}, E_{B}, E_{C},$ and $E_{D}$ respectively then

E_{A} = E_{C} > E_{B} = E_{D}

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E_{A} = E_{B} > E_{C} = E_{D}

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E_{A} = E_{B} = E_{C} = E_{D}

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E_{A} = E_{C} < E_{B} = E_{D}

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Solution

The correct option is A $E_{A} = E_{C} > E_{B} = E_{D}$

$E_{A}, E_{B}, E_{C}, E_{D}$ respectively parallel line the same electric field and higher line of force is higher electric field.
Hence,
$E_{A} = E_{C} > E_{B} = E_{D}$ .

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Similar questions

If $E_{A}, E_{B}, E_{C} a n d E_{D}$ represent the magnitudes of electric fields at A, B, C and D. Which of the options are correct?

2 A^{⊝} + B_{2} \to 2 B^{⊝} + A_{2}; 2 C^{⊝} + B_{2} \to N o r e a c t i o n; 2 D^{⊝} + A_{2} \to 2 A^{⊝} + D_{2}

\to E

E_{A}, E_{B}

E_{C}

If $E_{A}, E_{B}, E_{C} a n d E_{D}$ represent the magnitudes of electric fields at A, B, C and D. Which of the options are correct?

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