The given figure shows three blocks in contact and kept on a smooth horizontal surface. What is the ratio of force exerted by block A on B to that of B on C?
A
3:1
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B
1:3
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C
2:3
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D
3:2
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Solution
The correct option is A 3:1 All the block will move with same acceleration given by, a=16/(5+2+1) Now, force on A by B will be given by F=16−(5∗2)N F=6N Again force on B by C will be given by, F=6−(2∗2)N F=2 N Ratio will be 3:1