wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The given figure shows three blocks in contact and kept on a smooth horizontal surface. What is the ratio of force exerted by block A on B to that of B on C?
135442.png

A
3:1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1:3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2:3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3:2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3:1
All the block will move with same acceleration given by,
a=16/(5+2+1)
Now, force on A by B will be given by
F=16(52)N
F=6N
Again force on B by C will be given by,
F=6(22)N
F=2 N
Ratio will be 3:1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon