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Question

The given figure shows three resistors of 2Ω, 4Ω and RΩ connected to a battery of EMF 2V and internal resistance 3Ω.A main current of 0.25 A flows through the circuit.

(a) What is the potential difference across the 4Ω resistor?
(b) Calculate the potential difference across the internal resistance of the cell.
(c) What is the potential difference across the RΩ or 2Ω resistors?
(d) Calculate the value of R.
[5 MARKS]

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Solution

part a: 1 Mark
part b: 1 Mark
part c: 2 Marks
part d: 1 Mark

Given that current in the circuit = 0.25A
Current through 4Ω resistor = 0.25A
(a) Potential difference across 4Ω resistor
=R×I=4×0.25=1 V
(b) Potential difference across 3Ω (internal resistance of the cell) = R × I
=3×0.25=0.75 V
(c) the potential difference accross the RΩ or 2Ω resistors = 20.751=0.25V

(d) Current through the 2Ω resistance =0.252=0.125 A
Now ,V=IRR=VI
On substituting the values we get:
R=0.250.125=2Ω

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