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Question

The given relation is sin2(5212)osin2(2212)o=3+142

A
True
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B
False
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Solution

The correct option is A True
sin25212sin22212=sin(5212+2212)sin(52122212)
=sin75sin30
=12sin(45+30)
=12×3+122
=3+142
So the given relation is True

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