The given rhombus ABCD is symmetrical about the __.
Diagonal AC
Diagonal BD
Line passing through the midpoint of AB and DC
Line passing through the midpoint of AD and BC
A rhombus has two lines of symmetry. The diagonals AC and DB are the lines of symmetry of the rhombus.
ABCD is a quadrilateral in which AB || DC and AD || BC. A line MN, parallel to CD, is drawn meets the midpoint M of the side BC which meets AD at N. What can you say about the diagonal AC?
ABCD is a trapezium in which AB ⃦CD and AD =BC (see the given figure). Show that (i) ∠A = ∠B (ii) ∠C=∠D (iii) △ABC ≅△BAD (iv) Diagonal AC=diagonal BD [Hint: Extend AB and draw a line through C parallel to DA intersecting AB produced at E.]
Construct a rhombus ABCD, if ;
(i) AB = 4 cm and ∠B=120∘.
(ii) BC = 4.7 cm and ∠B=75∘
(iii) CD = 5 cm and diagonal BD = 8.5 cm.
(iv) BC = 4.8 cm, and diagonal AC = 7 cm.
(v) diagonal AC = 6 cm and diagonal BD = 5.8 cm.
(vi) diagonal AC = 4.9 cm and diagonal BD = 6 cm.
(vii) diagonal AC = 6.6 cm and diagonal BD = 5.3 cm.