The gram molecules in $21$ g of nitrogen is: $[N = 14]$ .

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Solution

The gram molecules in $21 g$ of nitrogen
Gram Molecular Mass of Nitrogen if $28 g$
No. of moles $= \frac{G i v e n m a s s}{G r a m M o l e c u l a r M a s s} = \frac{21}{28} = \frac{3}{4}$
$1$ mol contains $⟶ 6.022 \times 10^{23}$ gram molecules
$\frac{3}{4}$ mol contains $⟶ \frac{3}{4} \times 6.022 \times 10^{23}$
$⟶ 4.51 \times 10^{23}$ gram molecules
Therefore, the gram molecules in $21 g$ of nitrogen is $4.51 \times 10^{23}$ gram molecules

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The gram molecules in 21g of nitrogen is: [N=14].

The gram molecules in $21$ g of nitrogen is: $[N = 14]$ .