Question

The graph above represents the pressure and volume for a gas undergoing a cyclic process. Assume that Y and Z are on the same horizontal line, and Z and X are on the same vertical line. The part of the cyclic process from X to Y is an isothermal process.
If the pressure of the gas at X is $4.0kPa$, and the volume is $6.0$ cubic meters, and if the pressure at Y is $8.0kPa$, what is the volume of the gas at Y? (The graph is not necessarily drawn to scale)

• A. $12.0$ cubic meters
• B. $16.0$ cubic meters
• C. $3.0$ cubic meters
• D. $4.0$ cubic meters
• E. $2.0$ cubic meters

Answer 1

Answer: (C)

$3.0$ cubic meters

Given : $P_X=4.0$ kPa $V_X=6.0$ $m^3$ $P_Y=8.0$ kPa

Process X to Y is an isothernal process : $P_X{V}_X=P_Y{V}_Y$

$\therefore$ $4.0\times 6.0=8.0\times V_Y$ $⟹V_Y=3.0$ $m^3$