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Pressure and Temperature

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The graph between log x/m v/s log P is straight line inclined at an angle 45degree with intercept 0.30. What will be rate of adsorption at pressure 0.4atm.

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Similar questions

Q. The graph between

log \frac{x}{m} v / s log P

is straight line inclined at an angle

45^{\circ}

0.30

. What will be rate of adsorption at pressure

0.4 a t m

?

Q. The graph between log

\frac{X}{m}

v/s log P is straight-line inclined at an angle

45^{o}

with intercept 0.30. What will be the rate of adsorption at pressure of 0.4 atm?

Q. Graph between log

(\frac{x}{m})

l o g p

is a straight line at an angle

45^{\circ}

with intercept on y-axis at 0.3010. Calculate the amount of gas adsorbed in gram per gram of the adsorbent when pressure is

0.2 a t m

Q. Graph between log

\frac{x}{m}

P

is a straight line inclined at an angle

45^{o}

. When pressure of

0.5 a t m

l o g k = 0.699,

the amount of solute adsorbed per

g

of adsorbent will be (Given, antilog 0.699 = 5)

Q. Graph between

log (\frac{x}{m})

log P

is a straight line at an angle

45^{\circ}

with intercept on

y

0.3010

. The amount (in

g

) of the gas absorbed per

g

of the adsorbent when pressure is

0.2 a t m

is:
(Assume that the adsorption obey Freundlich isotherm)

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