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Ideal Gas Equation

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The graph between log(x/m) vs log P is straight line inclined at an angle 45 with intercept 0.30. What will be rate of adsorption at pressure 0.4atm?

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Similar questions

Q. The graph between

log \frac{x}{m} v / s log P

is straight line inclined at an angle

45^{\circ}

0.30

. What will be rate of adsorption at pressure

0.4 a t m

?

Q. The graph between log

\frac{X}{m}

v/s log P is straight-line inclined at an angle

45^{o}

with intercept 0.30. What will be the rate of adsorption at pressure of 0.4 atm?

Q. Graph between

log (\frac{x}{m})

log P

is a straight line at an angle

45^{\circ}

with intercept on

y

0.3010

. The amount (in

g

) of the gas absorbed per

g

of the adsorbent when pressure is

0.2 a t m

is:
(Assume that the adsorption obey Freundlich isotherm)

Q. When a graph is plotted between

log \frac{x}{m}

log p

, it is a straight line with an angle

45^{\circ}

0.3010

y -

axis. If initial pressure is

0.3 atm

. what will be the amount of gas adsorbed per

g

log (\frac{x}{m})

log p

is a straight line at angle

45^{\circ}

O A

as shown. The value of

(\frac{x}{m})

at a pressure of

0.2 a t m

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