Question

The graph between the displacement (S) and time (t) for a particle moving in a straight line is shown in figure. During the intervals OA, AB, BC and CD, the acceleration of the particle is.

• A. OA +, AB 0, BC +, CD +
• B. OA -, AB 0, BC +, CD 0
• C. OA +, AB 0, BC -, CD +
• D. OA -, AB 0, BC -, CD 0

Answer 1

The correct option is B OA -, AB 0, BC +, CD 0

Internal OA, $\frac{d^s}{d{t}^2}<0$

Acceleration is negative.

Internal AB, $\frac{d^s}{d{t}^2}=0$

Acceleration is Zero.

Internal BC, $\frac{d^s}{d{t}^2}>0$

Internal CD, V=constant

$\frac{dV}{dt}=0$