The graph between the resistive force F acting on a body and the position of the body travelling in a straight line is shown in the figure. The mass of the body is 25 kg and initial velocity is 2 m/s.When the distance covered by the bodyi s 4 m, its kinetic energy would be

50 J

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40 J

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20 J

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10 J

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Solution

The correct option is D 10 J
Area under graph= total work by resistive force = 0.5bh= 0.5420= 40J
$K E$ at $4 m$ in ideal condition = $0.5 m v^{2}$ = $0.5 (25) (2)^{2} = 50 J$
$K E$ at $4 m$ in presence of friction $= 50 - 40 = 10 J$

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