Question

The graph of kinetic energy of photoelectron versus frequency of incident radiation is shown for two metals $M$ and $N$. We may definitely conclude:

• A. work function of $M>$ work function of $N$
• B. work function of $M<$ work function of $N$
• C. work function of $M=$ work function of $N$
• D. at the threshold frequency of $M$ the kinetic energy of the photoelectron emitted by $M$ is more than that emitted by $N$

Answer 1

The correct option is A work function of $M>$ work function of $N$

Work function $=h{v}_0$
As the threshold frequency of $M$ is more than that of $N$, its work function is also more.