Question

The graph of $PV$ vs $P$ at two temperatures $T_1$ and $T_2$ is shown below. What is the correct order about $T_1$ and $T_2$?

• A. $T_1>T_2$
• B. $T_2>T_1$
• C. $T_1=T_2$
• D. $T_1+T_2=1$

Answer 1

The correct option is B $T_2>T_1$

From boyles law, at constant temperature
PV = constant
Thus,
$PV\text{vs}P$ graph is a straight line horizontal to the pressure axis at constant $T$.
As we know for an ideal gas, $PV=nRT$
Hence, for a given amount of the gas, $PV\propto T$
So, at higher temperature the value of $PV$ will be higher.
$T_2>T_1$