The graph of $| x | + | y | = 1$ is

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Solution

The correct option is B
Given : $| x | + | y | = 1$
$| y | = 1 - | x | \Rightarrow y = \pm (1 - | x |)$
We know $y = | x |$

So $y = - | x |$

For $y = 1 - | x |$ , shifting $y = - | x |$ upwards by $1$ unit.

Now, taking mirror image about $x -$ axis, we get
$y = - (1 - | x |)$
Hence, the graph of $| x | + | y | = 1$ is

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| x | + | y | = 1

=

^{- 1}

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then what is the graph of y = (x + 1)^{3} ?

| x | + | y | + | x + y | = 1

y = coth (x)

y

{coth}^{- 1} (x)

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