The graph shown below depicts plot of photocurrent versus anode potential for a cathode with 4 eV work function. The energy of the incident photon is
It is given that
Work function
ϕ=4eV
V=2V
From Einstein’s relation
hν=ϕ+Ek
Where hν is the energy of photons. And Ek is the kinetic energy
hν=(4+2)eV
hν=6eV