The graph shows variation of internal energy U with density ρ of one mole of an ideal monatomic gas. The process AB is a part of rectangular hyperbola. Find the work done (in J) in the process.
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Solution
For rectangular hyperbola, Uρ=Constant TV=Constant P=Constant
So, the gas undergoes isobaric process W=nRΔT˙....(i)
From graph, change in internal energy n(Cv)ΔT=3 n(3R2)ΔT=3 ⇒nRΔT=3 ⇒W=2J
Final answer: (2)