Question

The gravitational force between two objects is proportional to $\frac{1}{R}$ (and not as $\frac{1}{R^2}$) where $R$ is separation between them, then a particle in a circular orbit under such a force would have its orbital speed $\nu$ proportional to

• A. $\frac{1}{R^2}$
• B. $R^0$
• C. $R^1$
• D. $\frac{1}{R}$

Answer 1

The correct option is B $R^0$

Since, $\frac{GMm}{R}=\frac{m{v}^2}{R}$

So, $v\propto R^0$