The gravitational force between two stones of mass $1 k g$ each, separated by a distance of $1 m$ in a vacuum is ( $G = 6.674 \times 10^{- 11} N m^{2} / k g^{2}$ )

Zero

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6.674 \times 10^{- 5} N

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6.674 \times 10^{- 8} N

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6.674 \times 10^{- 11} N

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Solution

The correct option is D $6.674 \times 10^{- 11} N$
Using universal law of gravitation,
$F = \frac{G m M}{R^{2}}$
Distance between two stones, $R = 1 m$
Mass of both the stones, $m = M = 1 k g$
$F = \frac{G (1 k g) (1 k g)}{(1 m)^{2}}$
$F = 6.674 \times 10^{- 11} N$

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Q. The gravitational force between two identical objects at a separation of 1 m is 0.0667 mg wt. The masses of the objects are:

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Calculate the force between two masses of 100 kg and 1000 kg separated by a distance of 10 m ( $G = 6.67 \times 10^{- 11}$ N $\frac{m^{2}}{k g^{2}}$ ).

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The gravitational force between two stones of mass 1 kg each, separated by a distance of 1 m in a vacuum is (G=6.674×10−11Nm2/kg2)

The correct option is D 6.674×10−11NUsing universal law of gravitation,F=GmMR2Distance between two stones, R=1 mMass of both the stones, m=M=1 kgF=G(1 kg)(1 kg)(1 m)2F=6.674×10−11N

The gravitational force between two stones of mass $1 k g$ each, separated by a distance of $1 m$ in a vacuum is ( $G = 6.674 \times 10^{- 11} N m^{2} / k g^{2}$ )

The correct option is D $6.674 \times 10^{- 11} N$
Using universal law of gravitation,
$F = \frac{G m M}{R^{2}}$
Distance between two stones, $R = 1 m$
Mass of both the stones, $m = M = 1 k g$
$F = \frac{G (1 k g) (1 k g)}{(1 m)^{2}}$
$F = 6.674 \times 10^{- 11} N$