Question

The greaest height to which a man can throw a stone is h. The greatest distance to which he can throw it, will be :

Answer 1

Range of a projectile $R=\frac{v_0^2}{2g}\sin 2\theta$

A body travels a maximum distance when the angle of projectile is ${45}^0$

Thus $R_{max}=\frac{v_0^2}{2g}\sin 90$

as $\sin 90=1$

$R_{max}=\frac{v_0^2}{2g}$