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Question

The greatest acceleration or deceleration that a train may have is a. The minimum time in which the train can get from one station to the next at a distance s is:


A
sa
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B
2sa
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C
2sa
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D
12sa
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Solution

The correct option is C 2sa
The time will be minimum if it get accelerated to half distance then other hall distance let retreated
So using s=ut+12at2 ; u=0 (initially at rest)
We have s2=12at21
t1=sa it is time to cover half (i.es2) distance with acceleration a
other half (s2) in all be covered in same time because retarelation is also a so total time t=2t1=2sa
Option C is correct



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