The greatest number that will divide 37, 50, 123 leaving remainder 1, 2 and 3 respectively is

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Solution

The correct option is D 12
$37 - 1 = 36, 50 - 2 = 48$
$123 - 3 = 120$
HCF of 36, 48 and $120 = 12$
$∴$ required number $= 12$ .

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