The greatest number that will divide $37, 50, 123$ leaving remainder $1, 2$ and $3$ , respectively is

9

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10

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15

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12

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Solution

The correct option is D $12$
$37 - 1 = 36$ ,
$50 - 2 = 48$ ,
$123 - 3 = 120$
HCF of $36, 48 a n d 120 = 12$
$∴$ required number $= 12$

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