The H.C.F of a2−5a+6 and a−3 is a−2. Find their L.C.M.
A
(a−3)
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B
(a−3)2
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C
(a−2)2
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D
(a−2)(a−3)2
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Solution
The correct option is B(a−3)2 Given: f(x)=a2−5a+6 g(x)=a−3 H.C.F =a−2 Factor of a2−5a+6=(a−2)(a−3) Using the formula, f(x)×g(x)=H.C.F×L.C.M L.C.M =(a−2)(a−3)(a−3)(a−2) L.C.M =(a−3)2