The H-C-F of the fraction 821- 1235327- nbsp-

8 = 2^3 12 = 2^2 × 3 32 = 2^5 HCF H.C.F(8,12,32) = 2^2 = 4 21 = 3 × 7 35 = 5 × 7 LCM(21,35, 7) = 3 × 5 × 7 = 105 HCF of a fraction = HCF of numerator / LCM of d ...

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Standard VII

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Shahajiraje and Jijabai

The H.C.F of ...

Question

The \(H.C.F\) of the fraction \(\dfrac{8}{21}, \dfrac{12}{35}\dfrac{32}{7}\)

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Solution

\(8 = 2^3\)
\(12 = 2^2 \times 3\)
\(32 = 2^5\)
HCF \(H.C.F(8,12,32) = 2^2 = 4\)
\(21 = 3 \times 7\)
\(35 = 5 \times 7\)
\(LCM(21,35, 7) = 3 \times 5 \times 7 = 105\)
\(HCF\) of a fraction = \(HCF\) of numerator / \(LCM\) of denominator
\(HCF\) of fraction \(= \dfrac{4}{105}\)

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Mam/Sir please give me prime fraction method H.C.F & Division method of H.C.F

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The \(H.C.F\) of the fraction \(\dfrac{8}{21}, \dfrac{12}{35}\dfrac{32}{7}\)

\(8 = 2^3\) \(12 = 2^2 \times 3\) \(32 = 2^5\) HCF \(H.C.F(8,12,32) = 2^2 = 4\) \(21 = 3 \times 7\) \(35 = 5 \times 7\) \(LCM(21,35, 7) = 3 \times 5 \times 7 = 105\) \(HCF\) of a fraction = \(HCF\) of numerator / \(LCM\) of denominator \(HCF\) of fraction \(= \dfrac{4}{105}\)

\(8 = 2^3\)
\(12 = 2^2 \times 3\)
\(32 = 2^5\)
HCF \(H.C.F(8,12,32) = 2^2 = 4\)
\(21 = 3 \times 7\)
\(35 = 5 \times 7\)
\(LCM(21,35, 7) = 3 \times 5 \times 7 = 105\)
\(HCF\) of a fraction = \(HCF\) of numerator / \(LCM\) of denominator
\(HCF\) of fraction \(= \dfrac{4}{105}\)