Question

The H-O-O bond angle in $H_2{O}_2$ is:

• A. ${107.28}^o$
• B. ${109.28}^o$
• C. ${104.5}^o$
• D. ${94.8}^o$

Answer 1

Answer: (D)

${94.8}^o$

The oxygen in water has two lone pairs of electrons just like each oxygen in hydrogen peroxide. The decreased bond angle in hydrogen peroxide compared to water $\left({104.5}^{\circ }\right)$. about the $O-O$ single bond. The OH bond length is 1.796 a.u., the $O-O$ bond length $2.788$ a.u., the $H-O-O$ angle $94.8.$

$\therefore$ The bond angle of $H-O-O$ is $94.8$