The hardness of water sample which contains $0.001$ mol $M g S O_{4}$ per litre of water is:

400

ppm

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300

ppm

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200

ppm

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100

ppm

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Solution

The correct option is B $100$ ppm
Given that the water sample contains $0.001$ mol of $M g S O_{4}$ per litre of water.
Therefore, the hardness of water sample is $\frac{0.001 \times 100}{1000} \times 10^{6} = 100$ ppm.

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