The head scale of a screw gauge has 100 divisions and the screw moves 4 mm ahead in four rotations of the circular head. The pitch and the least count are respectively

1 mm, 0.01 mm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.01 mm, 1 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.1 mm, 0.001 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.001 mm, 0.1 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
1 mm, 0.01 mm

We know that, Pitch = $\frac{(D i s t a n c e t r a v e l l e d o n t h e p i t c h s c a l e)}{(N o . o f r o t a t i o n s o f t h e h e a d s c a l e)}$ = $\frac{(4 m m)}{(4)}$ = 1 mm

Also, Least Count = $\frac{(P i t c h)}{(N o . o f d i v i s i o n s o f t h e h e a d s c a l e)}$ = $\frac{(1 m m)}{(100)}$ = 0.01 mm

Suggest Corrections

Similar questions

The head scale of a screw gauge has 100 divisions and the screw moves 4 mm ahead in four rotations of the circular head. The pitch and the least count are respectively

Q. What is the least count of a screw gauge if the head scale of a screw gauge contains 100 divisions and its pitch is 1 mm?

Q. The circular scale (head scale) of a screw gauge is divided into

100

equal parts and it moves

0.5 m m

ahead in one rotation. The pitch and the least count are:

Q. A screw gauge has the least count of

0.01 mm

and there are

50

divisions in its circular scale. The pitch of the screw gauge is :

Q. A screw gauge has

500

scale on its head scale and the head scale moves

5

mm when rotated

10

times, then determine the pitch and least count of the screw gauge.

Join BYJU'S Learning Program

The head scale of a screw gauge has 100 divisions and the screw moves 4 mm ahead in four rotations of the circular head. The pitch and the least count are respectively

The correct option is A 1 mm, 0.01 mm We know that, Pitch = (Distance travelled on the pitch scale)(No. of rotations of the headscale) = (4mm)(4) = 1 mm Also, Least Count = (Pitch)(No. of divisions of the head scale) = (1mm)(100) = 0.01 mm