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Question

The head scale of a screw gauge has 100 divisions and the screw moves 4 mm ahead in four rotations of the circular head. The pitch and the least count are respectively


Solution

We know that, Pitch = (Distance travelled on the pitch scale)(No. of rotations of the head scale) = (4mm)(4) = 1mm

Also, Least Count = (Pitch)(No. of divisions on the head scale) = (1mm)(100)= 0.01mm

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