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Question

The heat energy absorbed by a system in going through a cyclic process shown in figure is
8820.JPG

A
103πJ
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B
102πJ
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C
104πJ
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D
107πJ
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Solution

The correct option is B 102πJ
Since process is cyclic, change in internal energy ΔU=0
Applying first law of thermodynamics,
ΔQ=ΔU+ΔW
ΔQ=ΔW = Area under the ellipse= πab
Here, length of semi major axis=a=10=b=length of semi minor axis
Hence, heat absorbed= 102π J

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