The correct option is B 102πJ
Since process is cyclic, change in internal energy ΔU=0
Applying first law of thermodynamics,
ΔQ=ΔU+ΔW
ΔQ=ΔW = Area under the ellipse= πab
Here, length of semi major axis=a=10=b=length of semi minor axis
Hence, heat absorbed= 102π J