1
Question
The heat of formation of C2H5OH(l) is −66 kcal mol−1. The heat of combustion of CH3OCH3 (g) is −348 kcal mol−1. △Hf for H2O and CO2 are −68 kcal mol−1 and −94 kcal mol−1 respectively.
Then, the △H for the reaction C2H5OH(l)→CH3OCH3(g) is:
Then, the △H for the reaction C2H5OH(l)→CH3OCH3(g) is:
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Solution
Given,
△Hof of C2H5OH(l)=−66 kcal mol−1
2C(s)+12O2(g)+3H2(g)→C2H5OH(l)
∴△H1=−66 kcal mol−1 ....(1)
Again,
ΔHoC of CH3OCH3= −348 kcal mol−1
CH3−O−CH3(g)+3O2(g)→2CO2(g)+3H2O(l)
△H2=−348 kcal mol−1 ...(2)
H2(g)+12O2(g)→H2O(l)
△H3=−68 kcal mol−1 (Given) ...(3)
C(s)+O2(g)→CO2(g)
△H4=−94 kcal mol−1 (Given) ....(4)
Then for reaction,
C2H5OH(l)→CH3OCH3(g)
This reaction can be obtained by the combination
= - eq.(1) - eq.(2) + 3 [eq.(3)] + 2 [eq.(4)]
So, △H for the above isomerisation reaction can be obtained by ;
△H=+66+348−3×68−2×94=+66+348−204−188
⇒ △H=22 kcal mol−1
△Hof of C2H5OH(l)=−66 kcal mol−1
2C(s)+12O2(g)+3H2(g)→C2H5OH(l)
∴△H1=−66 kcal mol−1 ....(1)
Again,
ΔHoC of CH3OCH3= −348 kcal mol−1
CH3−O−CH3(g)+3O2(g)→2CO2(g)+3H2O(l)
△H2=−348 kcal mol−1 ...(2)
H2(g)+12O2(g)→H2O(l)
△H3=−68 kcal mol−1 (Given) ...(3)
C(s)+O2(g)→CO2(g)
△H4=−94 kcal mol−1 (Given) ....(4)
Then for reaction,
C2H5OH(l)→CH3OCH3(g)
This reaction can be obtained by the combination
= - eq.(1) - eq.(2) + 3 [eq.(3)] + 2 [eq.(4)]
So, △H for the above isomerisation reaction can be obtained by ;
△H=+66+348−3×68−2×94=+66+348−204−188
⇒ △H=22 kcal mol−1
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