The heat of transition (ΔHt) of graphite into diamond would be, where, C(graphite)+O2(g)→CO2(g)ΔH=xkJ C(diamond)+O2(g)→CO2(g)ΔH=ykJ
A
x+y kJ/mole
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B
x−y kJ/mole
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C
y−x kJ/mole
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D
None of these
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Solution
The correct option is Bx−y kJ/mole To calculate: C(graphite)→C(diamond) Heat of reaction will be equal to the heat of transition Given: C(graphite)+O2(g)→CO2(g)ΔH=xkJ CO2(g)→C(diamond)+O2(g)ΔH=−ykJ So, by adding the two, required ΔH = (x−y) kJ/mole