The heat required to rise the temperature of 54 g of aluminium from $40^{\circ} C$ to $60^{\circ} C$ in J is (molar heat capacity of aluminium in this temperature range is 24 $J m o l^{- 1};$ atomic weight of Al is 27 g)

480

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800

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960

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1280

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Solution

The correct option is C 960
$C = \frac{q}{△ T}$
where C is the heat capacity , $△ T$ is the difference in temperature and q is amount of heat or energy given per mole.
$q = n C △ T (1)$
$n = \frac{54}{27} = 2$ substitute in eqn. (1)
$q = 2 \times 24 \times 20 = 960 J o u l e$

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Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from $35^{\circ} C$ to $55^{\circ} C$ . Molar heat capacity of Al is $24 J m o l^{- 1} K^{- 1}$

Q. Molar heat capacity of aluminium is

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. The heat necessary to raise temperature of

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27 g m o l^{- 1}

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Q. Molar heat capacity of aluminium is 25

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. The heat necessary to raise the temperature of 54 g of aluminium (Atomic mass

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Q. Calculate the heat necessary to raise the temperature of 60g of aluminium from 35

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The heat required to rise the temperature of 54 g of aluminium from 40∘C to 60∘C in J is (molar heat capacity of aluminium in this temperature range is 24 Jmol−1; atomic weight of Al is 27 g)

The correct option is C 960C=q△T where C is the heat capacity , △T is the difference in temperature and q is amount of heat or energy given per mole. q=nC△T (1) n=5427=2 substitute in eqn. (1) q=2×24×20=960 Joule

The heat required to rise the temperature of 54 g of aluminium from $40^{\circ} C$ to $60^{\circ} C$ in J is (molar heat capacity of aluminium in this temperature range is 24 $J m o l^{- 1};$ atomic weight of Al is 27 g)

The correct option is C 960
$C = \frac{q}{△ T}$
where C is the heat capacity , $△ T$ is the difference in temperature and q is amount of heat or energy given per mole.
$q = n C △ T (1)$
$n = \frac{54}{27} = 2$ substitute in eqn. (1)
$q = 2 \times 24 \times 20 = 960 J o u l e$