The heats of neutralization of four acids A, B, C and D are -13.7, -9.4, -11.2 and -12.4 $k c a l m o l^{- 1}$ respectively, when they are neutralized by a common base. The acidic character obeys the order:

A > B > C > D

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A > D > C > B

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D > C > B > A

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D > B > C > A

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Solution

The correct option is B A > D > C > B
The enthalpy of neutralization $(Δ H_{n})$ is the change in enthalpy that occurs when one equivalent of an acid is neutrilized with one equivalent of a base to form water and a salt. Lower is heat of neutralization, more is heat of dissociation of acid, weaker is acid.

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