Question

The height and radius of the coke tin is 14 cm and 5 cm respectively. How many litres of coke is present in the tin?
$(\pi =\frac{22}{7})$ [1 MARK]

Answer 1

Formula: 0.5 Mark
Application: 0.5 Mark

$h=14,r=5$

Volume of the coke tin = $\pi r^{2}h$

$=\frac{22}{7}\times 5^2\times 14$

$=1100{cm}^3$

Volume of the coke $=1100{cm}^3=1.1l$.