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Standard XI

Chemistry

Pressure and Temperature

The height of...

Question

The height of water $ρ = 1000 k g / m^{3}$ and oil $ρ = 720 k g / m^{3}$ are 6 m and 5m inside an open barometer. What is the atmospheric pressure in kPa?

136.42 kPa

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65.98 kPa

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101.25 kPa

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91.34 kPa

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Solution

The correct option is D 91.34 kPa
We know, pressure of the oil and water will balance the atmospheric pressure
$P_{o i l} + P_{w a t e r}$ = Atmospheric pressure $(P_{a t m}$ )
$P_{a t m}$ = $720 \times g \times 6$ + $1000 \times g \times 5$
$P_{a t m}$ = 91336 Pa = 91.34 kPa

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Pressure and Temperature

Standard XI Chemistry

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The height of water ρ=1000kg/m3 and oil ρ=720kg/m3 are 6 m and 5m inside an open barometer. What is the atmospheric pressure in kPa?

The correct option is D 91.34 kPaWe know, pressure of the oil and water will balance the atmospheric pressure Poil+Pwater = Atmospheric pressure (Patm) Patm = 720×g×6 + 1000×g×5 Patm = 91336 Pa = 91.34 kPa

The height of water $ρ = 1000 k g / m^{3}$ and oil $ρ = 720 k g / m^{3}$ are 6 m and 5m inside an open barometer. What is the atmospheric pressure in kPa?

The correct option is D 91.34 kPa
We know, pressure of the oil and water will balance the atmospheric pressure
$P_{o i l} + P_{w a t e r}$ = Atmospheric pressure $(P_{a t m}$ )
$P_{a t m}$ = $720 \times g \times 6$ + $1000 \times g \times 5$
$P_{a t m}$ = 91336 Pa = 91.34 kPa