The Henry-s law constant for the solubility of N 2 gas in water at 298 K is 1-0 - 105 atm- The mole fraction of N 2 is 0-8- The number of moles of N 2 from air dissolved in 10 moles of water at 298 K and 5 atm pressure isA- 4 - 10-5B- 5 - 10-4C- 4 - 10-6D- 4 - 10-4

1.The Henry's law constant for the solubility of N2gas in water at 298k is 10^5 atm.The mole fraction of N2 is 0.8.Find the number of N2 from air dissolved in 10 moles of water at 298K and 5 atm pressure

2.How many moles in 1litre of water

Q. The Henry's law constant for the solubility of

N_{2}

gas in water at

298 K

1 \times 10^{5}

atm. The mole fraction of

N_{2}

in air is

0.8

. Calculate the number of moles of

N_{2}

dissolved in

10 m o l e s

of water at

298 K

and

5 a t m

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The Henry's law constant for the solubility of N2 gas in water at 298K is 1.0 x 105 atm. The mole fraction of N2 is 0.8. The number of moles of N2 from air dissolved in 10 moles of water at 298K and 5 atm pressure is

The correct option is A 4 x 10-4

The Henry's law constant for the solubility of N₂ gas in water at 298K is 1.0 x 10⁵ atm. The mole fraction of N₂ is 0.8. The number of moles of N₂ from air dissolved in 10 moles of water at 298K and 5 atm pressure is

The correct option is A 4 x 10^-4